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Topic: Benzedrine - Old Book Synthesis
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Rhenium Member |
posted 01-25-99 06:45 AM
Hi all Bee's,
Whilst I was looking wistfully through the index of another old chem
book which I had collected, when mine eyes drifted accross this reference
for the synthesis of Benzedrine.
Pheylacetic acid + Acetone in the presence of Sodium Acetate and with
heat give Phenylacetone.
Then react phenylacetone with NH2OH to give the the oxime, then
reduction with H2 and Pt to give the final product.
This is interesting for two reason I guess. First they say that this is
a commercial synthesis, and secondly because although I've seen sodium
acetate used before (the Russian reference in CA) I've never seen it used
in conjunction with acetone.
Suggestions anyone? The book is
pg 219-220 A Modern Introduction to Organic Chemistry, William B
Smith Charles E Merrill Books Inc, Columbus Ohio 1961 -- Congress
number 61-10942
They also give a nice synth for novocaine.
Rhenium
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Beagle Member |
posted 01-25-99 11:26 AM
You never can tell what kind of useful info may turn up in an old
textbook, but I suspect that this is a typo here, acetone should read
acetic anhydride.
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ChemHack Member |
posted 01-25-99 12:21 PM
Perhaps the Sodium Acetate plays the role of the Acetic Anhydride?
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ChemHack Member |
posted 01-25-99 12:28 PM
Hmmmmm...... dunno about that but here is another idea: Sodium Acetate is
used to prepare Acetic Anhydride, with acetyl chloride I think.... ?
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Piglet Member |
posted 01-26-99 09:33 AM
I cannot comment on the P2P production, other than to say it sounds real
interesting. The bit I'm into is the use of NH2OH as the source of the NH2
species. Oximes can be reduced in a number of cool ways. Acidic (in
formic) or basic (in NaOH) Zn reductions, hydride reductions, and of
course the hydrogenation using Pt. The only small fly in the ointment
seems to be the oxime formation. Water soluable ketones are easy (just
dH2O with NH2OH.HCl and something to buffer pH). Water insoluable ketones
require slightly more messing. Shulgin amongst others uses an alcoholic
solution with pyridine (no fun) or maybe NH4/Na/K acetate (CA 61,6953
[1964]).
Could you outline the oxime formation for me, thanks
Piglet
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Rhenium Member |
posted 01-27-99 07:56 AM
Hi everyone,
I can't really give much more detail, because there wasn't much more
than that in the book. They definitely used acetone (dimethyl ketone,
2-propanone - call it what you will) as they had the structure presented
there.
Unfortunately that was about all. The oxime formation was not
particularly clear, just an arrow over the page and voila there's the
oxime. The details are so sketchy I can't even say what the solvent was
used for that step. I will have another look, but details are scanty.
Rhenium
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psychokitty Member |
posted 01-27-99 10:20 AM
Any references in there? If there are, look them up as I'm sure they'll
indicate details to the reaction mechanism, even if the syntheis of
phenylacetone is not given as one of their examples.
--Psychokitty
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Labrat Member |
posted 01-27-99 10:39 AM
Rhenium, surely you must smell something fishy about this synth:
phenylacetate + acetone -> phenylacetone.
I just can't believe that the whole acetate moiety can be replaced with
acetone.
It would be possible to condense phenylacetic acid with acetone like
with acetic anhydride. In that case the alpha-carbon of phenylacetic acid
is deprotonated and the anion condenses with acetone, forming an
intermediate which decarboxylates and ... about here the intermediate
should lose a methylgroup if we want P2P to form.
Does anyone have better suggestions? Or better yet, Rhenium, can you
provide us with a ref? Thanks. Lr/
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Beagle Member |
posted 01-27-99 11:45 AM
I could see how acetone and phenylacetic acid could condense with a very
strong base, but sodium acetate? Maybe under pressure/heat, but no way
with simple reflux.
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Labrat Member |
posted 01-28-99 09:52 AM
How do you explain then that phenylacetic acid and acetic anhydride
condense with sodium acetate as added base (at high temperatures)? The
phenylacetic acid is easily deprotonated at the alpha-carbon because this
carbon atom is both attached to a phenyl group and a carboxyl group.
When the alpha-carbon is deprotonated, the charge is delocalised over
the carboxyl and maybe the phenylgroup. Fact is, that sodium acetate or
pyridine are strong enough bases to do the job.
But this was all pretty clear to me. What I don't understand is why
phenylacetone is formed in the condensation of phenylacetic acid and
acetone. Do you have a clue Beagle? Lr/
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psychokitty Member |
posted 01-28-99 12:24 PM
I'll just say this much so that I can take a different stance than
everybody:
I believe you Rhenney. I really do.
--Psychokitty
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Beagle Member |
posted 01-28-99 12:54 PM
Labrat: Nope, I'm pretty clueless generally. But I see the mechanism of
the acetic anhydride/PAA condensation as not involving a deprotonation
directly. Maybe I'm off base here, but seems like PAA would form a mixed
anhydride with the Ac2O. Now the alpha hydrogens become much more acidic,
and deprotonation, or much more likely, polarization can occur on the
alpha carbon that allows the condensation to take place. In the case of
PAA/acetone, where a mixed anhydride cannot form, the carboxyl proton will
be MUCH more acidic. Thus, it will have to dissociate first. This very
much decreases the acidity of the alpha proton. You need something on the
order of butyllithium to get the dianion of PAA.
And I take back what I said about seeing how PAA and acetone could
condense, even with strong base. Too many carbons in acetone, you'd have
to lose one somewhere. Until someone comes up with a decent mechanism or
ref on this, I have to stand by my statement that this is a typo.
Maybe if there was acetic ACID present, and enough heat, there could be
in situ generation of an equilibrium of acetic anhydride from the sodium
acetate.
I have been known to postulate why known reactions aren't possible
before, but I think that I'm right on this one.
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Beagle Member |
posted 01-28-99 01:06 PM
Boy I hate eating my words so soon after they come out of my mouth.
OK, maybe I see how it could work, but the acetone plays no role here
except as solvent: PAA and Na acetate form a mixed anhydride first. Next
this condenses with another molecule of the mixed anhydride or acetic
anhydride formed from the acetate. The acetylated PAA can now be
decarboxylated to give P2P, as in the PAA/Ac2O synthesis.
The only problem I see with this is that sodium acetate and PAA are not
going to want to form the anhydride. Maybe with mucho heat, under
pressure.
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Osmium Member |
posted 01-28-99 01:40 PM
One of the first P2P syntheses was done by pyrolysis of an intimate
mixture of PAA and Ba(OAc)2. Strange that the same reaction should take
place in acetone.
Another example: Ca(OAC)2 ---heat---> acetone
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Beagle Member |
posted 01-28-99 02:05 PM
Do you have any idea what is going on in the reaction Ca(OAC)2
---heat---> acetone ?
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Osmium Member |
posted 01-28-99 02:47 PM
No.
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Rhodium Administrator |
posted 01-28-99 03:26 PM
In the Ca(OAc)2 => acetone thing, it is pretty clear to me that the
acetate pyrolyzes (into Ac- and CaOAc+), and then the cation sucks an
electron from the anion, precipitating the stable CaO, and creates two
free radical Ac* which immediately combines to give acetone. Or perhaps
it's free radicals all the way ( CaOAc => CaO + 2 Ac* ), what do I
know?
Regarding the P2P synth, there is a reaction called the Fries
rearrangement, in which phenylacetate is reacted with AlC3 to form
2-hydroxy-phenylacetone, but NaOAc isn't exactly AlCl3...
There is also this ref, found in MV Smith's "Psychedelic Chemistry":
Amphetamines from Phenylacetates CA 35, 5868 (1941)
Add 0.44 moles ring substituted phenylacetate, 100 g acetic anhydride
and 30 g sodium acetate and heat at 145-150°C for 18 hours to get ca. 0.4
moles of the methyl-phenylacetate (I). Add (I) and formamide (or
N-methyl-formamide for the N-methyl cpd.), heat 4-5 hours at 180-195°C,
cool and extract with CHCl3. Evaporate in vacuum, dissolve residue in 40%
sulfuric acid and heat at 90-125°C for 5-6 hours. Neutralize and add solid
NaOH to precipitate about 50% amphetamine. Treat with 10% sulfuric acid to
get the sulfate.
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Osmium Member |
posted 01-29-99 03:27 AM
THIS IS THE RUSSIAN REF I WAS SEARCHING SO BAD!
Of course they do not use "phenlyacetate", they use PAA; and they do
not produce "methyl-phenylacetate", they make P2P. This procedure works
as stated, I did it with 80% yield. The workup is a bit tricky, as it is
not given in the ref. Someone I know hydrolysed the still refluxing
reaction by adding water through the condensor. He had to repaint the
ceiling and the walls.
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Labrat Member |
posted 01-29-99 10:07 AM
Beagle: you're right, if there's phenylacetate and acetic anhydride,
you'll get formation of the mixed anhydride, then deprotonation. The free
carboxylic acid will indeed be much less basic.
But I do think that acetone is playing a part here. If it only served
as a solvent, it would be pretty worthless. The bp of acetone is 57 C and
the rxn will prolly occur at much higher temperature (like the
phenylacetate/acetic anhydride condensation), so the acetone would be
evaporated before the rxn started. I may be wrong on this if the rxn
temperature is <60 C, so correct me here if you can.
But I still don't see the mechanism of the condensation here. Would it
be like Beagle suggested, that a mixed anhydride is formed in acetone,
which decarboxylates? That would make the rxn temperature <60 C and
this would be a VERY good synth! Or would a sealed vessel and high
temperatures be necessary? I wish we could finally get a ref on this, so
we could clear things up a bit. Lr/
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Rhenium Member |
posted 01-29-99 11:03 AM
Hi everyone,
I have started a bit of a discussion here. It's very late at night,
and all I can say is that the book seems to indicate that acetone might be
one of the reactants. They have PAA + Acetone --> phenylacetone. Now
when I see a plus sign, I think reactant, not solvent.
Can someone else find this book to prove that I'm not hallucinating?
I'm going to be away at a conference for two weeks and won't be able to
provide anymore details.
Rhenium
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Beagle Member |
posted 01-29-99 12:29 PM
Rhenium: Have a good time!
Rhodium & Osmium: I noticed that method in Psych. Chem. too, but
never realized that it refered to PAA and P2P. I guess that if you kind of
look at it funny, then you could call P2P methyl-phenylacetate! But I
always thought it was talking about the ester, and wondered what the hell
was going on.
And regarding adding water to hot acetic anhydride, I know what you
mean!
Labrat: I don't think that there is any way that acetic or mixed
anydride forms here at <60 deg. And the decarboxylation is DEFINATELY
not occuring under these conditions. If the reaction is indeed progressing
as I suggested, then pressure would be a must in order to get the heat up.
Sounds like Rhen's book is just giving the basic outline, maybe they left
out the seperate decarboxylation step. Or decarboxylation cold occur after
removal of the solvent, under heat/vacuum.
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niteflier Member |
posted 01-29-99 10:25 PM
hmmmm...I never did figure out the mechanics of the synth from PAA, NaA,
and AA, but the synth outlined in the M.V.Smith book works well....also
can say for sure that AA ( acetic anhydride ) is not needed if you use
lead acetate instead of Na. Wouldnt recommend using PAA and lead acetate
though, (although yeilds are good), as you need really vicious vacuum to
distill as high temps will destroy your glassware with a residual
lead/crud cake. I guess if you have strong enough vacuum it would be
OK.....hope I give someone sharper than me a clue as to the exact
mechanics of this rxn....
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niteflier Member |
posted 01-30-99 03:45 PM
On rhodium's homepage, posted by drone 342, is a discussion and
description of P2P via the enolate of acetone......?
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Labrat Member |
posted 01-31-99 04:21 PM
Rhenium: I already checked my library for that book. It wasn't in there.
Beagle: maybe this was an industrial process for preparing P2P? There's
an indication of what is reacted with what, but I need rxn conditions like
temperature, pH, stirring, etc! We could continue the discussion on the
mechanism of this rxn for quite some time, but I think it's best to wait
until somebody finds that book in their library and get a ref on this.
It's prolly all explained in there. Lr/
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hummmm Member |
posted 12-20-1999 02:06 AM
I aint never head of half that shit tlake dabout iin such an idoot version
are you fucking rushian or speak pig
latin>>>>>>>>.................
FUCK
WHORES>>>>>>>>>>>>>................
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Xaja Member |
posted 12-20-1999 02:27 AM
Wow FMAN has dragged up something interesting here. Maybe
he is useful after all.
But using Pb acetate in place of AA is not the go - bad yields. Anyway,
it's PAA that's hard to come by these days.
But it would be cool to know whether PAA + acetone + Na acetate runs or
not. Anyone?
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CHEMMAN Member |
posted 12-20-1999 04:11 AM
Thought Id throw this one in.I was in a uni library researching benzedrine
synths in old books.Little details were given,but two ingredients were
analine and acetone .!!!!!! I dont remember all but these two stick in
my mind.
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